-0.000192x^2+0.02x=0

Solution for -0.000192x^2+0.02x=0 equation:

-0.000192x^2+0.02x=0

a = -0.000192; b = 0.02; c = 0;
Δ = b2-4ac
Δ = 0.022-4·(-0.000192)·0
Δ = 0.0004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.02)-\sqrt{0.0004}}{2*-0.000192}=\frac{-0.02-\sqrt{0.0004}}{-0.000384}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.02)+\sqrt{0.0004}}{2*-0.000192}=\frac{-0.02+\sqrt{0.0004}}{-0.000384}
$